Player information: Jonathan Welton (2022 - 2023 season)




Listed below are details for Jonathan Welton who has played in nine matches during the 2022 - 2023 season:

Personal information
Club Crowthorne
  • Jonathan Welton Jonathan Welton
    Jonathan Welton, Crowthorne
ECF rating code 193645B
ECF membership code ME008042
ECF membership expires August
ECF membership category Bronze
Standard-play rating 1696, K
Rapid-play rating 1650, K
National Federation en.png
SBL first registered 01-09-2005
SBL registration status Yes
All season(s) summary
season match(es)
2023-24 season 7 matches
2022-23 season 9 matches
2021-22 season 4 matches
2019-20 season 8 matches
2018-19 season 13 matches
2017-18 season 5 matches
2016-17 season 15 matches
2015-16 season 18 matches
2014-15 season 18 matches
2013-14 season 17 matches
2012-13 season 8 matches
2011-12 season 16 matches
2010-11 season 18 matches
2009-10 season 15 matches
2008-9 season 23 matches
2007-8 season 18 matches
2006-7 season 13 matches
2005-6 season 7 matches
 
2022 - 2023 season performance statistics
Date Match Division Type SP/RP Opponent Board Result
24-10-2022 Guildford RA vs Crowthorne RA Division R OTB RP Pascoe Rapacci r1613K four win
09-11-2022 Crowthorne B vs Guildford E 4 OTB SP Anthony Garrood s1758K one loss
24-11-2022 Farnham A vs Crowthorne A 1 OTB SP Sam Kammin s1815K five loss
07-12-2022 Crowthorne A vs Sandhurst A 1 OTB SP Dylan Wastney s1464K five loss
08-12-2022 Farnham C vs Crowthorne B 4 OTB SP Helen M Frostick s1686K one win
16-01-2023 Guildford F vs Crowthorne C 5 OTB SP Peter Gabriel s1676P one win
23-01-2023 Guildford A vs Crowthorne A 1 OTB SP Sebastian E Galer s2064K five loss
06-02-2023 Guildford E vs Crowthorne B 4 OTB SP Pascoe Rapacci s1724K two loss
08-03-2023 Crowthorne B vs Godalming B 4 OTB SP Iain Reeve s1709K two draw
 
Performance summary for 2022 - 2023 season
Number of standard-play games: 8
Number of rapid-play games: 1
Standard-play performance:  +2  =1  -5  = 31.3%  (with all games completed)
Rapid-play performance:  +1  =0  -0  = 100%